5+2x(x-3)=2x^2

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Solution for 5+2x(x-3)=2x^2 equation: 



5+2x(x-3)=2x^2

We move all terms to the left:

5+2x(x-3)-(2x^2)=0

determiningTheFunctionDomain
-2x^2+2x(x-3)+5=0

We multiply parentheses

-2x^2+2x^2-6x+5=0

We add all the numbers together, and all the variables

-6x+5=0

We move all terms containing x to the left, all other terms to the right

-6x=-5

x=-5/-6

x=5/6

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